In general, the recommended fertilization amount for the soil testing formula fertilization table is the amount of pure nitrogen, p2o5 (phosphorus pentoxide), and k2o (potassium oxide). However, due to the different effective content of various fertilizers, it is difficult for farmers to accurately grasp the amount of fertilizer used in the actual production process. The following is a simple method for calculating the amount of fertilizer applied to the soil.
Assume that the recommended amount of fertilizer for this plot is 8.5 kg of pure nitrogen per mu, p2o 54.5 kg, and k2o 6.5 kg. Single fertilization. The calculation method is as follows: Recommended fertilization amount ÷ The effective content of ÷ fertilizer = the amount of fertilizer to be applied. The following results can be obtained: urea (toluene nitrogen content is generally 46%) is 8.5 ÷ 46% = 18.5 (kg).
The application of the compound fertilizer is carried out by applying potassium sulfate (the content of k2o in potassium sulfate is generally 50%) to 6.5 ÷ 50% = 13 (kg). If a compound fertilizer is applied, the amount should be calculated first by the type of fertilizer recommended on the formula fertilization table, and then the other two fertilizers should be added. If the nitrogen, phosphorus and potassium content of a certain compound (combined) fertilizer bag is 15:15:15, then the compound should be applied with this compound: 4.8÷15%=32 (kg). In this way, the phosphorus in the soil has already met the nutrients needed by the crop. Due to the fixed proportion of compound fertilizer, it is difficult to meet the demand for various nutrients in different soils of different crops. Therefore, it is necessary to add unit fertilizer to supplement, and the formula is: (recommended fertilization amount - applied fertilizer amount) 有效 effective amount of fertilizer to be applied = supplemented fertilization amount. The plot has been applied with 32 kg of compound fertilizer with 15% NPK, which is equivalent to 32×15% of pure nitrogen in soil, 4.8 (kg), p2o5 and k2o are also 4.8 kg each. According to the recommended dosage of pure nitrogen 8.5 kg and k2o 6.5 kg on the table, it is necessary to increase the application: urea (8.5-4.8) ÷ 46% = 8 (kg), potassium sulfate (6.5-4.8) ÷ 50% = 3.4 (kg).
Assume that the recommended amount of fertilizer for this plot is 8.5 kg of pure nitrogen per mu, p2o 54.5 kg, and k2o 6.5 kg. Single fertilization. The calculation method is as follows: Recommended fertilization amount ÷ The effective content of ÷ fertilizer = the amount of fertilizer to be applied. The following results can be obtained: urea (toluene nitrogen content is generally 46%) is 8.5 ÷ 46% = 18.5 (kg).
The application of the compound fertilizer is carried out by applying potassium sulfate (the content of k2o in potassium sulfate is generally 50%) to 6.5 ÷ 50% = 13 (kg). If a compound fertilizer is applied, the amount should be calculated first by the type of fertilizer recommended on the formula fertilization table, and then the other two fertilizers should be added. If the nitrogen, phosphorus and potassium content of a certain compound (combined) fertilizer bag is 15:15:15, then the compound should be applied with this compound: 4.8÷15%=32 (kg). In this way, the phosphorus in the soil has already met the nutrients needed by the crop. Due to the fixed proportion of compound fertilizer, it is difficult to meet the demand for various nutrients in different soils of different crops. Therefore, it is necessary to add unit fertilizer to supplement, and the formula is: (recommended fertilization amount - applied fertilizer amount) 有效 effective amount of fertilizer to be applied = supplemented fertilization amount. The plot has been applied with 32 kg of compound fertilizer with 15% NPK, which is equivalent to 32×15% of pure nitrogen in soil, 4.8 (kg), p2o5 and k2o are also 4.8 kg each. According to the recommended dosage of pure nitrogen 8.5 kg and k2o 6.5 kg on the table, it is necessary to increase the application: urea (8.5-4.8) ÷ 46% = 8 (kg), potassium sulfate (6.5-4.8) ÷ 50% = 3.4 (kg).
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